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1ƒR[ƒi[ 5(13,14)-(6,12)10(3,9)2,4,7=8-11=1
2ƒR[ƒi[(2Žü–Ú) 5(13,14)(6,12)2,9-3(10,7)-(4,8)-11=1
3ƒR[ƒi[(2Žü–Ú) 5(13,14)(6,12,2)-3,9,7-8=11,4=10=1
4ƒR[ƒi[(2Žü–Ú) 5-(13,14)2-6(9,7)-3=8=(11,4)=(10,1)
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