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2ƒR[ƒi[ 4=3-2,11(12,14)(9,5)(1,7,10)8-6=13
3ƒR[ƒi[(2Žü–Ú) 4=3-2(12,14)-5=11,10,9,1=7(6,8)=13
4ƒR[ƒi[(2Žü–Ú) 4,3-2-12-5,14=10-1,11,9=(7,8)6=13
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