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1ƒR[ƒi[ 1-8=3,6-(13,10)4-5-11,7=9-2-12
2ƒR[ƒi[ 1=8-(3,6)(13,10)4-5-11=7=(2,9)-12
3ƒR[ƒi[(2Žü–Ú) 3-6(8,13)4,1-10(5,11)=7=9=12,2
4ƒR[ƒi[(2Žü–Ú) 3,13(4,6)-(8,10)(5,1,11)=7=9=12=2
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