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1ƒR[ƒi[ 1=(2,10)(7,13)(5,14,11)6(9,8)(3,4)=12
2ƒR[ƒi[ 1=13(2,11)7,5(10,14)(9,6)8(3,4)=12
3ƒR[ƒi[(2Žü–Ú) 1=13,11,7,6,4,3-5-(2,9)-14,8=10=12
4ƒR[ƒi[(2Žü–Ú) 1=(13,11)-7(6,4)-3-5-9-2,8,14=10=12
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